Alphabetizing a list in C, extra input -


this question has answer here:

sorry remedial question. been troubleshooting try , find error , have come empty.

i need write program alphabetizes list of inputs. first input integer value of number of inputs. each input ends new line character.

int main() {     int word_total;     char word_in[100][30], t[30];     int i, j;      printf("\nplease number of words wish sort: \n");     scanf("%d", &word_total);      printf("\nplease enter single word @ time. after each word, press return.\n");      (i = 0; < (word_total); i++)     {         scanf("%s\n", word_in[i]);     }      (i = 1; < (word_total); i++)      {            (j = 1; j < (word_total); j++)          {                if (strcmp(word_in[j - 1], word_in[j]) > 0)              {                    strcpy(t, word_in[j - 1]);                 strcpy(word_in[j - 1], word_in[j]);                 strcpy(word_in[j], t);               }         }     }      printf("\nsorted list:\n");     (i = 0; < (word_total); i++)     {         printf("%s\n", word_in[i]);     }     printf("\n"); }

the problem: input of words takes word_total + 1. instance, if word_total = 5, have input 6 words. last word input ignored , not included in "sorted list". can fix problem by:

for (i = 0; < (word_total - 1); i++)     {         scanf("%s\n", word_in[i]);     }

but "sorted list" short 1 word. i've tried changing "<" "<=", etc, haven't found fix.

thank help!

the problem seems be

scanf("%s\n", word_in[i]);

which, due "\n", attempt read more whitespace following string (until finds non-whitespace; note any whitespace character means any number of whitespace characters; \n not match single newline apparently expect). should remove "\n" scanf format , eat newline getchar() or similar.

ps: not testing return value scanf() asking trouble.


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