Controlling whitespace/newlines in XSLT output -


i've been searching through questions see if particular one's been answered no success. if missed it, apologies.

i have need "flatten" individual xml nodes output single line. whitespace between nodes not needed, , newlines within text nodes tobe replaced special character ('\n').

an example xml:

<events>   <event>     <id>123</id>     <type>read</type>     <description>       text here     </description>   </event> </events> 

what i'd output is:

<events> <event><id>123</id><type>read</type><description>\nsome text here\n</description></event> </events> 

i tried using <xsl:strip-space> tag, , takes care of whitespace between tags, doesn't touch newlines in side element.

i tried adding following template:

<xsl:template match="text()">   <xsl:copy-of select="translate(.,'&#xa;','\n')"/> </xsl:template> 

but seems remove tags , output text.

help?

your sample xml input document:

<events>   <event>     <id>123</id>     <type>read</type>     <description>       text here     </description>   </event> </events> 

given xslt 2.0 transformation:

<?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/xsl/transform" version="2.0">    <xsl:strip-space elements="*"/>   <xsl:output method="xml" indent="no" omit-xml-declaration="yes"/>    <xsl:template match="*|@*">     <xsl:copy>       <xsl:apply-templates select="node()|@*"/>     </xsl:copy>   </xsl:template>    <xsl:template match="text()">     <xsl:value-of select="replace(., '[ \t\r]*\n[ \t\r]*', '\\n')"/>   </xsl:template>  </xsl:stylesheet> 

produces requested xml output document:

<events><event><id>123</id><type>read</type><description>\nsome text here\n</description></event></events> 

Comments

Popular posts from this blog

commonjs - How to write a typescript definition file for a node module that exports a function? -

openid - Okta: Failed to get authorization code through API call -

ios - Change Storyboard View using Seague -