javascript - How to display an alert when only three of nine checkboxes are checked? -


i have implemented following code website produce alert when 3 checkboxes named "correct" checked.

<input type="checkbox" name="correct"/> <input type="checkbox" name="correct"/> <input type="checkbox" name="correct"/>  const correctinputs = [...document.queryselectorall('input[name="correct"]')];  const alertifthree = () => {   const checkedcorrectinputs = correctinputs.filter(input => input.checked);   if (checkedcorrectinputs.length > 2) {     alert('alert');   } };  correctinputs.foreach(input => input.addeventlistener('click', alertifthree));

however, have 6 checkboxes named "incorrect" , when of these checkboxes checked don't want alert produced, if 3 "correct" checkboxes checked.

<input type="checkbox" name="incorrect"/> <input type="checkbox" name="incorrect"/> <input type="checkbox" name="incorrect"/> <input type="checkbox" name="incorrect"/> <input type="checkbox" name="incorrect"/> <input type="checkbox" name="incorrect"/>

how can change code implement this? in advance!

you can keep same logic

const correctinputs = [...document.queryselectorall('input[name="correct"]')]; const incorrectinputs = [...document.queryselectorall('input[name="incorrect"]')];  const alertifthree = () => {     const checkedcorrectinputs = correctinputs.filter(input => input.checked);     const checkedincorrectinputs = incorrectinputs.filter(input => input.checked);      if (incorrectinputs.length === 0 && checkedcorrectinputs.length > 2) {         alert('alert');     } };

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