Python invalid syntax on conditional -


i have python code here:

def location(location_id, max_id=none):         # send http request find location         if (self.login_status):             get_location = {'location_id': location_id}             url_location_detail = self.url_location_detail % (location_id)         try:             get_location_id = self.i.get(url_location_detail, data=body)             if location.status_code == 200:                log_string = "get location id: %d" % (location_id)                self.write_log(log_string)          if max_id not none: payload['max_id'] = max_id             try:                 res = requests.get(url, params=payload).json()                 body   = res['location']                 cursor = res['location']['media']['page_info']['end_cursor']             except: raise             return instagramexploreresponse(data=body, cursor=cursor)

when run program, raises following error:

syntaxerror: invalid syntax

the error seems show @ line 447 following:

if max_id not none: payload['max_id'] = max_id

the weird thing code working before , added code before line think error comes previous line.

unfortunately, can't see it.

thanks!

you can find need here: putting simple if-then statement on 1 line

they explain why error showing , ways solve it

being more clear here, can't put inside if in front of if in python. this:

if max_id not none: payload['max_id'] = max_id

become this:

if max_id not none:     payload['max_id'] = max_id

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