Php equal more or less operators -


i getting following error:

$experience = $row[experience]; use of undefined constant experience - assumed 'experience' – user3696343 )

from code:

} else if($_get['event'] == 15) {       $fetch = mysqli_query($db_handle, "select gold, bank, troop, head, body, gloves, foot, combatlog, item0, item1, item2, item3, coordinatex, coordinatey, coordinatez, horse, hp, new, food, experience, level playerdata unique_id = '$unique_id'");       $row = mysqli_fetch_assoc($fetch);      $experience = $row[experience];       $xptolevel = '50';       if($experience >= $xptolevel) {       echo'enough xp level up';        mysqli_query($db_handle, "update playerdata set experience = 0, level = level + 1 unique_id = '$unique_id'");            echo "15|$unique_id|$local_id|$row[gold]|$row[bank]|$row[troop]|$row[head]|$row[body]|$row[gloves]|$row[foot]|$row[combatlog]|$row[item0]|$row[item1]|$row[item2]|$row[item3]|$row[coordinatex]|$row[coordinatey]|$row[coordinatez]|$row[horse]|$row[hp]|$row[new]|$row[food]|$row[level]|$row[experience]|";       } else {       echo'not enough xp level up';   }   }

i hope can help

when access associative array element, add quotes:

$row[experience] becomes $row['experience']

if use experience, assumes trying use constant experience doesn't exist php converts string you. works, notice.

if need use within quotes, use {} around it:

echo "some string {$row['experience']}";

finally, sql code not safe. use parametrized queries instead of injecting actual variables in sql.


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