python - Creating a list with two different numbers -

i have 2 numbers x , y. x example 1.5, , y 1.5 need create list of lists 8 different values.

[[0.5,0.5],[0.5,1.5],[0.5,2.5], [1.5,0.5],[1.5,1.5],[1.5,2.5], [2.5,0.5],[2.5,1.5],[2.5,2.5]]  [1.5,1.5] #needs removed above list. 

how can in python 3 using different x , y values? x , y numbers between 1 , 10. 1.5 or 2.5 or 3.5 etc.

try using following list comprehension:

items = [[a, b] in items b in items if x != or y != b] 

as such:

>>> x = 1.5 >>> y = 1.5 >>> items = [x-1, x, x+1] >>> items = [[a, b] in items b in items if x != or y != b] >>> items  [[0.5, 0.5], [0.5, 1.5], [0.5, 2.5], [1.5, 0.5], [1.5, 2.5], [2.5, 0.5], [2.5, 1.5], [2.5, 2.5]] >>>  

edit:

or, if list comprehension confusing, can change nested for loops:

for in items:     j in items:         if != x or j != y:             cp.append([i, j]) 

this runs as:

>>> x = 1.5 >>> y = 1.5 >>> items = [x-1, x, x+1] >>> cp = [] >>> in items: ...     j in items: ...         if != x or j != y: ...             cp.append([i, j]) ...  >>> items = cp >>> items [[0.5, 0.5], [0.5, 1.5], [0.5, 2.5], [1.5, 0.5], [1.5, 2.5], [2.5, 0.5], [2.5, 1.5], [2.5, 2.5]] >>>