In C++, how would I program an exception that catches any number over 10? -

i know sounds simple but...

i'm doing simple guessing game , i'm trying use try/throw/catch handle error of input of on 10. don't think teacher wants simple

if(x>10)  {  //do  }  

instead think wants do:

if(x>10)  {  throw dont_know_what_to_put ;  }   catch(dont_know_what_to_put)  {  //do  }  

how do throw , catch? throw , catch work exceptions , not random throws?

edit: want throw error if input on 10. catch error , output number out of range want.

and trust me, never want this, teacher's instructions unclear don't know if wants me inputs invalid using try/catch/throw or not.

if wanted impressive

 #include <stdexcep>   . . . .    throw std:range_error ("your message here") ;   . . . .   try {  } catch (std::exception &error) {     cerr << errror.what () << endl ; }