Python Regex: Finding files without a certain extension -


i'm trying figure out regular expression use in order search directory , return number of files in directory not have prefix 'abc_'. e.g, in directory files def_notes.txt, abc_notes.txt, ghi_notes.txt, function recognize there 2 files without 'abc_' prefix , return 2.

to point, i'm having trouble writing regular expression represent this. i've tried re.compile('^(.(?!(abc_)))*$') found here. however, doesn't seem work. leaving first dot inside parenthesis matches file 'abc_notes.txt'. if remove dot, won't match 'abc_notes.txt', doesn't match 'def_notes.txt'.

edit: clarify, i'll use glob or os packages work once figure out expression. i'm using re.compile , search in python shell figure out regex.

this code prints out how many files in current directory don't start letter z: 

import glob, re  print len( [path path in glob.glob('*')             if not path.startswith('z')             ]            )

the following code uses regular expression. matches letter 'z' @ beginning of string -- reverses match (?!...) syntax.

pat = re.compile('^(?!z)') print len( filter(none, map(pat.match, glob.glob('*'))) )

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