mysql - having an issue with php dropdown menus -


so i'm working on project requires users select dropdown menu. using following code can manage slots 1 & 2 display value. inserting other slots value of 0 working, not displaying values. if isn't clear enough please let me know , can try provide more information. code follows;

 echo' <br/>  slot 1  <select name="slot1">';  while($row = mysqli_fetch_array($result) , $i<10) { echo"<option value='"; echo$row['playerid'];    // sorry inverted commas trickys echo"'>"; echo $row['name']; echo "</option>";  $i=$i+1; }  echo '</select>';  echo' <br/> slot 2  <select name="slot2">'; $i=1; while($row = mysqli_fetch_array($result) , $i<10) { echo"<option value='"; echo$row['playerid'];    // sorry inverted commas trickys echo"'>"; echo $row['name']; echo "</option>";   $i=$i+1;  }  echo '</select>';  echo' <br/> slot 3  <select name="slot3">';   while($row = mysqli_fetch_array($result) , $i<10)  {   echo"<option value='";  echo$row['playerid'];    // sorry inverted commas trickys  echo"'>";  echo $row['name'];  echo "</option>";   $i=$i+1;  }   echo '</select>';   echo' <br/>  slot 4   <select name="slot4">';   while($row = mysqli_fetch_array($result) , $i<10)  {  echo"<option value='";  echo$row['playerid'];    // sorry inverted commas trickys  echo"'>";  echo $row['name'];  echo "</option>";  $i=$i+1; }  echo '</select>';  echo' <br/> slot 5  <select name="slot5">';  while($row = mysqli_fetch_array($result) , $i<10) { echo"<option value='"; echo$row['playerid'];    // sorry inverted commas trickys echo"'>"; echo $row['name']; echo "</option>";  $i=$i+1; }  echo '</select>';

you have reset $i value 1 before others slot:

$i=1;

or have think again how fill slot, same query ? wan same values each slot? in case need: mysqldataseek


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