Construct YAML that contains JSON data in python -


i have file config.json contains json follows:

{      "json":{         "type":"service",       "project":"project",       "key":"key",       "client":"client"    },    "project_id":"1" }

i want include json data in yaml file.

yaml (this required output):

contexts: - config:     json: |       {         "type": "service",         "project": "project",         "key": "key",         "client": "client"       }     project_id: "1"   name: cloud current-context: cloud

here, 2 keys json & project_id coming config.json data. json data added config under contexts.

the following underlines 2 information coming config.json data.

contexts: - config:     json: |     ----       {       }     project_id: "1"     ----------   name: cloud current-context: cloud

how can this?

i have tried below:

with open("config.json") f:     config = yaml.safe_load(f)  config_map = {} key in config:     config_map[key] = str(config[key])  context = dict(     config=config_map,     name="cloud", )  data = {     "contexts": [context],     "current-context": "cloud", }

but not correct.
can point me correct direction?

if want dump value key json literal block style scalar can use:

import sys ruamel import yaml  open("config.json") f:     config = yaml.safe_load(f)  key in config:     try:         int(config[key])         val = yaml.scalarstring.doublequotedscalarstring(config[key])     except typeerror:         val = yaml.round_trip_dump(             config[key], default_flow_style=true, width=10, default_style='"')         val = val.replace('{"', '{\n  "').replace('"}', '"\n}')         val = yaml.scalarstring.preservedscalarstring(val)     config[key] = val  context = dict(     config=config,     name="cloud", )  data = {     "contexts": [context],     "current-context": "cloud", }  yaml.round_trip_dump(data, sys.stdout)

which gives exactly required output. might want adjust try statement determines on gets rendered double quoted scalar, , literal block scalar.


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