python parse prints only first line from list -

i have list 'a',where need print matching letters of list line of text file 'hello.txt'.but prints first word list , line instead of list , lines

a=['comp','graphics','card','part']  open('hello.txt', 'r') f:     key in a:         line in f:             if key in line:                 print line, key 

it results as:

comp , python comp 

desired output:

comp , python comp graphics , pixel graphics micro sd card card python part part 

please me desires output.answers willbe appreciated!

the file-object f iterator. once you've iterated it, it's exhausted, for line in f: loop work first key. store lines in list, should work.

a=['comp','graphics','card','part'] open('hello.txt', 'r') f:     lines = f.readlines()  # loop file once , store contents in list     key in a:         line in lines:             if key in line:                 print line, key 

alternatively, swap loops, iterate file once. better if file big, won't have load it's contents memory @ once. of course, way output slights different (in different order).

a=['comp','graphics','card','part'] open('hello.txt', 'r') f:     line in f:     # file done once...         key in a:  # ... , key loop done multiple times             if key in line:                 print line, key 

or, suggested lukas in comments, use original loop , 'reset' file-iterator calling f.seek(0) in each iteration of outer key loop.