c++ - How can I access of a variable inside a lambda without using a global variable? -

i'm not sure, maybe can me.

how can access variable inside lambda? example:

float lim;  int main() {   std::cin >> lim;   std::vector<float> v = {1.0f,4.5f,3.9f,0.2f,8.4f};   v.erase(std::remove_if(v.begin(),v.end(),[](float f){return f > lim}),v.end());   (auto : v) std::cout << i;   return 0; } 

so example works, can specify value 'lim' , values in vector bigger lim remove inside vector. how can avoiding global variable lim hold value?

thanks.

use lambda with capture. notice [&].
here demo.

#include <iostream> using namespace std;  int main() {     int k=0;int n=0;      auto func1=[=]()mutable{k=1;n=1;};  //capture k value     func1();     std::cout<<k<<std::endl;  //print 0      auto func2=[&](){k=2;n=1;};         //capture k reference     func2();     std::cout<<k<<std::endl;  //print 2  (k changed)      auto func3=[k]()mutable{k=3;/* n=1; compile fail*/}; //capture k value     func3();     std::cout<<k<<std::endl;  //print 2      auto func4=[&k](){k=4;      /* n=1; compile fail*/}; //capture k reference     func4();     std::cout<<k<<std::endl;  //print 4  (k changed) }  

more mutable : why c++0x's lambda require "mutable" keyword capture-by-value, default?