xml - how to get attribute value in xslt? -


culd yu please tell me how attribute value in xslt?. make variable in have full name(f) , short name (s). using full name want short name

here code http://xsltransform.net/ehvyzmp/1

<?xml version="1.0" encoding="utf-8" ?> <xsl:transform xmlns:xsl="http://www.w3.org/1999/xsl/transform" version="1.0" xmlns:exsl="http://exslt.org/common"  extension-element-prefixes="exsl">     <xsl:output method="html" doctype-public="xslt-compat" omit-xml-declaration="yes" encoding="utf-8" indent="yes" />       <xsl:variable name="teams">             <team f="sunrisers hyderabad" s="srh"></team>             <team f="delhi daredevils" s="dd"></team>             <team f="gujarat lions" s="gl"></team>             <team f="kings xi punjab" s="kxip"></team>             <team f="kolkata knight riders" s="kkr"></team>             <team f="mumbai indians" s="mi"></team>             <team f="rising pune supergiant" s="rps"></team>             <team f="royal challengers bangalore" s="rcb"></team>  </xsl:variable>   <xsl:variable name="up" select="'kings xi punjab'"/>     <xsl:template match="/">        <hmtl>         <head>           <title>new version!</title>         </head>         <xsl:value-of select="exsl:node-set($teams)/team[@f = $up]/@s"/>       </hmtl>     </xsl:template>   </xsl:transform>

expected output: kxip

see edited code @ http://xsltransform.net/ehvyzmp/8 answer.


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