ruby - Dynamically define a method inside an instance method -

i working on project of context-oriented programming in ruby. , come problem:

suppose have class klass:

class klass     def my_method         proceed     end end 

i have proc stored inside variable impl. , impl contains { puts "it works!" }.

from somewhere outside klass, define method called proceed inside method my_method. if call klass.new.my_method, result "it works".

so final result should that:

class klass     def my_method         def proceed             puts "it works!"         end         proceed     end end 

or if have other idea make call of proceed inside my_method working, it's good. proceed of method (let's my_method_2) isn't same my_method. in fact, proceed of my_method represent old version of my_method. , proceed of my_method_2 represent old version of my_method_2.

thanks help

disclaimer: you doing wrong!

there must more robust, elegant , rubyish way achieve want. if still want abuse metaprogramming, here go:

class klass   def self.proceeds     @proceeds ||= {}   end    def def_proceed     self.class.proceeds[caller.first[/`.*?'/]] = proc.new   end    def proceed *args     self.class.proceeds[caller.first[/`.*?'/]].(*args)   end    def m_1     def_proceed { puts 1 }     proceed   end    def m_2     def_proceed { puts 2 }     proceed   end end  inst = klass.new  inst.m_1 #⇒ 1 inst.m_2 #⇒ 2 

what in fact need, module#prepend , call super there.