java string split based on new line -

i have following string

string str="aaaaaaaaa\n\n\nbbbbbbbbbbb\n   \n"; 

i want break on \n @ end should 2 string aaaaaaaa , bbbbbbbb. dont want last 1 contain white space. if split based on new line character using str.split() final array should have 2 entry only.

i tried below:

string str="aaaaaaaaa\n\n\nbbbbbbbbbbb\n   \n".replaceall("\\s+", " "); string[] split = str.split("\n+"); 

it ignore \n , give single string aaaaaaaaaa bbbbbbbb.

delete call replaceall(), removing newlines too. do:

string[] split = str.split("\n\\s*"); 

this not split on spaces - split must start @ newline (followed optional further whitespace).

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here's test code using sample input edge case enhancement:

string str = "aaaaaaaaa\nbbbbbb bbbbb\n   \n"; string[] split = str.split("\n\\s*"); system.out.println(arrays.tostring(split)); 

output:

[aaaaaaaaa, bbbbbb bbbbb]