sql - How to find possible consecutive values and return the minimum and the maximum values of that series? -


i'm working on displaying weekly schedule , want merge appointments if consecutive , have no gaps.
for example: have7:00am - 08:00am , 08:00am - 03:00pm time schedule of doctor.

in other words, how find records have consecutive values same doctor , day of week, , return minimum value of start time , maximum value of end time of consecutive set.

is possible retrieve data , convert 07:00am - 03:00pm using sql? if how?

i'm using sql server 2008 r2 here sample data:

enter image description here

try following query:

;with gatherdates (     select docid,            starttime appointmenttime     appointment      union      select docid,            endtime     appointment ) ,removeduplicates (     select docid,            appointmenttime,            count(*) duplicatecount     gatherdates     group docid,              appointmenttime ) ,findcontinuosappointment (     select docid,            appointmenttime,            row_number() over(partition docid                               order appointmenttime asc) rn     removeduplicates     duplicatecount = 1 ) select st.docid,        st.appointmenttime starttime,        et.appointmenttime endtime findcontinuosappointment st inner join findcontinuosappointment et on st.docid = et.docid , st.rn = et.rn - 1 , st.rn % 2 = 1 , et.rn % 2 = 0;

check sql fiddle link: http://www.sqlfiddle.com/#!3/04b71/1/0

do let me know comments.


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