c# - Send parts of a byte[] by webclient to create a large file in server side -

so trying transfer large byte[] chose separate in chunks of 20mb, , in first chunk received create file , add that,the rest open existing file , add remaining.the problem having instead of send first part , reconnect receive second part establishing 2 connections , sending 2 chunks @ same time.. how can send second after first finished?

client.openwriteasync(ub.uri);   void client_openwritecompleted(object sender, openwritecompletedeventargs e) {     if (e.cancelled)     {         messagebox.show("cancelled");     }     else if (e.error != null)     {         messagebox.show("deu erro");     }     else     {         try         {             using (stream output = e.result)             {                 int countbytes;                  //for (int = 0; < max; i++)                 //{                 if ( (max+1) != maxaux)                 {                     countbytes = zippedmemorystream.read(partofdataset, 0 , 20000000);//maxaux * 20000000                     output.write(partofdataset, 0, (int)countbytes);                     if (max != maxaux)                     {                         client.openwriteasync(ub.uri);                       }                     maxaux++;                  }                  //}                  //numeroimagem++;             }         }         catch (exception ex)         {             messagebox.show(ex.message);             //throw;         }     } } 

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public void processrequest(httpcontext context) {     //context.response.contenttype = "text/plain";     //context.response.write("hello world");      string imagename = context.request.querystring["imagename"];     string uploadpath = context.server.mappath("~/serverimages/");      byte[] bytes = new byte[20000000];     int bytestoread = 0;      if (!file.exists(uploadpath + imagename))     {         using (filestream stream = file.create(uploadpath + imagename))         {              try             {                 //list<byte> bytes = new list<byte>();                   while ((bytestoread =                 context.request.inputstream.read(bytes, 0, bytes.length)) != 0)                 //context.request.inputstream.read(bytes, 0, 200000)) != 0)                 {                      stream.write(bytes, 0, bytestoread);                     stream.close();                  }                  bytes = null;             }             catch (exception ex)             {                 string error = ex.message;                 throw;             }          }     }     else     {         using (filestream stream = file.open(uploadpath + imagename,filemode.append))         {              try             {                  while ((bytestoread =                 context.request.inputstream.read(bytes, 0, bytes.length)) != 0)                 {                      stream.write(bytes, 0, bytestoread);                     stream.close();                  }                 bytes = null;              }             catch (exception ex)             {                 string error = ex.message;                 throw;             }          }     }  }  public bool isreusable {         {         return false;     } } 

in fact gain nothing opening client again. can loop on zippedmemorystream in chunks , write output stream. data arrive in order on server side.

otherwise uploaddata methods, if want create new connection each time.