Correct Line number when doing exception handling in python -


i use structure capturing , recording exception handling

1.  import sys 2. 3.  def break_python(): 4.      test1 = 1/0 5. 6.  def main(): 7.     #all main program functionality included in section 8.     break_python() 9.   10. if __name__ == "__main__": 11.     try: 12.         main() 13.     except exception e: 14.         print dir(e) 15.         print e.message 16.         type1,details,tb = sys.exc_info_() 17.         print type1 18.         print details 19.         print tb 20.         line_no = tb.tb_lineno 21.         print "line # " + str(line_no) 22.         print "failed run program"

when run primary program structure works line number print line 12 corresponding main() function call when want point function , line number of individual error, in case line 4 under function break_python()

i think looking traceback.print_exc(file=sys.stdout) see https://docs.python.org/2/library/traceback.html#traceback-examples


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