Python - Calling a script from another script and handling exceptions from the second one -


so have script, python script (call aaa.py) , calls method in python script (call bbb.py). method in bbb.py throws , handles keyerror exception when run aaa.py raises exception console if wasn't handled... , don't understand why. explain me please?

yes i've read documentation on exceptions in python.

here try/except:

try:     if network['network'] == vlans_dict[network['netname']]['netaddr']:         self.test_pass('network address matches vlan router: ' + str(network['network']))     else:         self.test_fail('network address not match vlan router: ' + network['netname'],                         'expected: ' + str(vlans_dict[network['netname']]['netaddr']),                         'actual: ' + str(network['network'])) except keyerror:     self.test_fail("no subnet obtained " + network['netname'] + " vlan info")

honestly ridiculous add rest of code...

so add bit more this... if run second script directly on it's own handles exception gracefully intended.

regards, j

right.... short answer: i'm absolute grade f**kin idiot...

longer answer: modifying copy of bbb.py not bbb.py aaa.py getting class path... code fine, wasn't running it!


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