c++ - How can I avoid this code duplication? -


i have 2 methods have same code except 2 methods call (and other details can parameterize). however, method calls have same signature, think can generalize them single method.

class a{     iapi* m_papi;     void m1();     void m2(); public:     void dothings(); }  void a::m1(){     int i;     bool b;         m_papi->method1( &i, &b );         //other stuff... }  void a::m2(){     int i;     bool b;         m_papi->method2( &i, &b );     //other stuff... }  void a::dothings(){     m1();     m2(); }

i can figure out how "parameterize" "other stuff" code, problem calls method1 , method2. think have use std::bind somehow, can't this...

void a::m( std::function<void(int*,bool*)> f ){     int i;     bool b;     f( &i, &b ); }  void a::dothings(){     m( std::bind( ???, m_papi ) ); //m1     m( std::bind( ???, m_papi ) ); //m2 }

the problem here m_papi not concrete class (it's interface implemented bunch of concrete classes), i'm not sure if can usual &class::method thing. suggestions?

use pointers member function.

#include <iostream> using namespace std;  struct iapi {     void method1(int * i, bool * b) {         *i = 1; *b = true;     }     void method2(int * i, bool * b) {         *i = 2; *b = false;     } };  class {     iapi* m_papi;     void m(void (iapi::*)(int*, bool*)); public:     a() : m_papi(new iapi()) {}     void dothings(); };  void a::m(void (iapi::*mptr)(int*, bool*)) {     int i;     bool b;         (m_papi->*mptr)( &i, &b );         cout << << ' ' << b << endl; }  void a::dothings(){     m(&iapi::method1);     m(&iapi::method2); }  int main() {     a;     a.dothings(); }

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