c++ - std::nothrow pretty much useless? -

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• will using new (std::nothrow) mask exceptions thrown constructor? 3 answers

nothrow constant: constant value used argument operator new , operator new[] indicate these functions shall not throw exception on failure, return null pointer instead.

but here in simple example, instead of returning null, new throws exception:

struct somestruct {     somestruct()      {         std::bad_alloc exception;         throw exception;     } };      int _tmain(int argc, _tchar* argv[])     {             somestruct* somestruct;             somestruct = new (std::nothrow) somestruct;              return 0;     } 

any explanation please? indicates, despite having (std::nothrow) parameter new still need put code in try...catch block.

std::nothrow means instead of std::bad_alloc being thrown on failure acquire memory, new expression returns nullptr. not mean new expression not ever throw.

if somestruct did not throw in constructor, new expression never throw.