python - how to find a selected vert's symmetrical pair on a maya mesh -


what best (fastest) method find given vertex's symmetrical pair (ie , vert on left side of mesh , right hand side equivalent) possible use open maya api in python or there better way?

you don't want check position of every vert against every other on , over, extremely slow.

a simple approach hash value - simple comparison operation - every vertex identical 2 verts symmetrical. luckily tuples - not lists!! - hashable. algorithm be:

  1. get position tuple each vert
  2. make dictionary (position: vertex) verts on 'left' (or 'up' or 'back' etc) side.

  3. make second dictionary (position: vertex) verts on opposite side, symmetry axis flipped: if doing left/right axis, left list 

    { (x, y, z) : "pcube1.vtx[0]" }  #etc

    and right list 

    { (-1 * x, y, z) : "pcube1.vtx[99]" } # , on

  4. any key duplicated in both dictionaries symmetrical, need collect keys show in both , verts each side represent:

    duplicates = [j j in leftdictionary if j in rightdictionary] pairs = [leftdictionary[k], rightdictionary[k] k in keys]

this won't super fast on big meshes should trick.

the 1 place may have issues if there floating point discrepancies between sides items visually symmetrical may not mathematically symmetrical. modify match numbers withing given tolerance by, say, quantizing values put tuples -- easy way blow them factor, 1000, , turn them integers. raw method errs on side of missing things symmetrical aren't exactly, quantized method may collapse multiple matches if close. i'd stick raw data unless it's failing need.


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